Physics: Suppose that the design parameters of the satellite s control system require that the angular velocity of the satellite not exceed 0.02 rad/s. If the astronaut is moving parallel to the x axis and the position of her center of mass when she attaches is (- 1.8, - 0.9, 0) m, what is the maximum relative velocity at which she should approach the satelfae?

Suppose that the design parameters of the satellite

LEXIEXO

22.01.2022

v=0.04m/s

Explanation:

To solve this problem we have to take into account the expression

$\omega=\frac{v}{r}$

where v and r are the magnitudes of the velocity and position vectors.

By calculating the magnitude of r and replacing w=0.02rad/s in the formula we have that

$|r|=\sqrt{(-1.18m)^2+(-0.9m)^2}=2.01m\\\\v=\omega r=(0.02\frac{rad}{s})(2.01m)=0.04\frac{m}{s}$

the maximum relative velocity is 0.04m/s

hope this helps!!

0,0(0 оценок)

sweetyus06

20.10.2022

7, -10, -2

Correct on Edge

0,0(0 оценок)