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01.03.2021 •
Physics
Suppose that the voltage across the resistor is held constant at 40 volts. If the resistance is steadily decreasing at a rate of 0.2 ohms per second, at what rate is the current changing at the moment that the resistor reaches 5 ohms?
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Ответ:
The current is increasing at a rate of 0.32 ampere per second.
Explanation:
The voltage of the resistor is modelled after Ohm's Law, which states that voltage is directly proportional to current:
(1)
Where:
- Voltage, measured in volts.
- Current, measured in amperes.
- Resistance, measured in ohms.
An expression for the rate of change in voltage is found by Differential Calculus:
(2)
Where:
- Rate of change in voltage, measured in volts per second.
- Rate of change in current, measured in amperes per second.
- Rate of change in resistance, measured in ohms per second.
If we know that , , and , then the rate of change in current is:
(3)
The current is increasing at a rate of 0.32 ampere per second.
Ответ:
Explanation:
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