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cutegirl0987
22.08.2019 •
Physics
Suppose you have three springs with force constants of k1 = k2 = k3 = 3.70 x 10^3 n/m. what is their effective force constant if one is hung from the other in series? you may assume the springs have negligible mass.
the answer should be in n/m.
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Ответ:
The effective force constant is 1233.33 N/m.
Explanation:
It is given that,
Force constant 1,![k_1=3.7\times 10^3\ N/m](/tpl/images/0188/2606/c9d3b.png)
Force constant 2,![k_2=3.7\times 10^3\ N/m](/tpl/images/0188/2606/cb8bf.png)
Force constant 3,![k_3=3.7\times 10^3\ N/m](/tpl/images/0188/2606/b0776.png)
The effective force constant if one is hung from the other in series is given by :
So, the effective force constant is 1233.33 N/m. Hence, this is the required solution.
Ответ:
Therefore, we have
Avg velocity = change in direction/change in time
Avg velocity = (150km - 30km)/(5h - 0h)
Avg velocity = 24km/hr south.