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avalianagames
27.03.2020 •
Physics
The cylindrical tub of a dryer in a laundromat rotates counterclockwise about a horizontal axis at 41.5 rev/min as it dries the clothes. If the diameter of the cylinder is 0.692 m, at what angle will a piece of cloth lose contact with the wall of the cylinder and fall down
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Ответ:
The angle that the piece of cloth will lose contact with the wall would be![37.31^{o}](/tpl/images/0567/0339/92c8b.png)
Explanation:
for a body moving in a circular path The net force is equal to the centripetal force and can be calculated thus;
mgsin θ = m
r
isolating sine θ
sin θ =
r/ g
where w is the angular velocity = 41.5 rev/min = 41.5 rev/min x 2π/60 secs = 4.34587 rad/s
r is the radius = = d/2 = 0.692/2 = 0.3145 m
g is the acceleration due to gravity = 9.8 m/![s^{2}](/tpl/images/0567/0339/c60b2.png)
sin θ = (
x 0.3145)/ 9.8
sin θ = 0.6061
θ =
0.6061
θ =![37.31^{o}](/tpl/images/0567/0339/92c8b.png)
Therefore the angle that the piece of cloth will lose contact with the wall would be![37.31^{o}](/tpl/images/0567/0339/92c8b.png)
Ответ:
the answer is N•m(2)/c(2)
Explanation: