The figure shows a cross section of three parallel wires each carrying a current of 15 A. The currents in wires A and C are out of the paper, while that in wire B is into the paper. If the distance R = 5.0 mm, what is the magnitude of the force on a 4.0-m length of wire C?
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Ответ:
0.018 N
Explanation:
From the given information;
We understood that A and C possess the same current direction, thus the force between them is said to be an attractive force.
Also, between B and C, there exist different current directions, thus, the force between them is said to be a repulsive force.
So, the force per unit length magnitude are as follows:
Similarly;
Thus, the net force acting on 4.0 - m length of the wire C is:
Thus, the magnitude of the force on a 4.0-m length of wire C = 0.018 N
Ответ:
C. There is a net force on the box.
Explanation:
If the box was stationary, sitting on the roof, the correct answer choice would be A. In this scenario, the box is fallign downward, meaning that there is a net force pushing the box downward.