tylermorehead1
11.03.2020 •
Physics
The magnitude of the magnetic field in a magnetic resonance imaging (MRI) machine can be as great as B = 2.0T . Under normal circumstances, this field cannot be shut off by just flipping a switch. Instead the magnitude needs to be carefully decreased to zero. In an emergency, however, the magnet can be "quenched" so that B reduces to zero in 20 s. Such a quench can cost thousands of dollars and likely damages the magnets. Assume that the magnetic field exists inside a cylinder of radius R = 400mm and length ? = 500mm .
How much magnetic potential energy is dissipated when the magnetic field is quenched in this way?
What is the average rate at which energy is dissipated?
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Ответ:
Explanation:
Average energy density of a magnetic field
= (1 / μ₀) x B²
= ( 1 / 4π x10⁻⁷ )x 2
= .159 x 10⁷ J / m³
Volume of space where field exists
= πr² x L
3.14 x .4² x .5 m³
= .2512 m³
Total energy contained in magnetic field
= .2512 x .159 x 10⁷
= 4 x 10⁵ J .
Rate of dissipation = 4 x 10⁵ / 20 J/s
= 2 x 10⁴ J /s
Ответ:
do you speak english
Explanation: