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Disd112984
21.08.2019 •
Physics
The measurement of an electron's energy requires a time interval of 1.2×10^−8 s . what is the smallest possible uncertainty in the electron's energy?
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Ответ:
Explanation:
The uncertainty in energy is given by![\Delta E=\frac{h}{2\pi \Delta t}](/tpl/images/0185/4173/3f589.png)
here h is plank's constant which value is
and
is the time interval which is given as ![1.2\times 10^{-8}sec](/tpl/images/0185/4173/45ec4.png)
So using all the parameters the smallest possible uncertainty in electrons energy is![=\frac{6.67\times 10^{-34}}{2\times \pi \times 1.2\times 10^{-8}}=1.05\times 10^{-26}J](/tpl/images/0185/4173/d487b.png)
Ответ:
y-intercept=15 b/c it is the b value in y=mx+b or you can plug in 0 for x, and get 15 also
x-intercept=3 b/c when y is 0, x is 3
slope= -5 b/c it is the value of m in y=mx+b