Physics: The number of loops in the primary coil divided by the number of loops in the secondary coil equals the voltage in the primary coil divided by the voltage in the secondary coil if the volunteer attached to the primary coil read 100 volts what would the voltmeter attached to the secondary coil read

The number of loops in the primary coil divided

amandanunnery33

09.03.2022

Answer : $V_{s} = 100\times\dfrac{N_{p}}{N_{s}}$

Explanation :

Given that, number of loop in the primary coil = $N_{p}$

Number of loop in the secondary coil = $N_{s}$

Voltage in primary coil = 100 Volt

Voltage in secondary coil = $V_{s}$

We know that

$\dfrac{N_{p}}{N_{s}} = \dfrac{V_{s}}{V_{p}}$

$V_{s} = 100\times\dfrac{N_{p}}{N_{s}}\ volt$

So, this is the required solution.

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penaabel1492

08.02.2021

Y a la gente que no se puede hacer un favor para hacer una prueba y se me pasa por la cabeza y no me puedo dormir was gonna we gonna

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