The position equation for a particle is s of t equals the square root of the quantity 2 times t plus 1 where s is measured in feet and t is measured in seconds. find the acceleration of the particle at 4 seconds. 3 ft/sec2 one third ft/sec2 negative 1 over 27 ft/sec2 none of these
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Ответ:
Given that,
s = √(2t + 1)
Time, t = 4 s
Acceleration , a = ??
Since,
Acceleration = velocity / time
Velocity = distance/ time
Acceleration = distance/ time²
s/t² = √(2t+1)/t²
putting t = 4 sec, we have
a = √(2*4+1)/4²
a = √(5)/16
a= 0.139 ft/s²
Therefore, acceleration of the given particle will be 0.139 feet/ second².
Ответ:
False
Explanation:
It's received in elliptical cavities.