Physics: The strength of an electric field at 5.0 cm from a point charge is 100.0 n/c. what is the magnitude of the source charge? show your work.

The strength of an electric field at 5.0 cm from

Ответ:

isiahb123

16.01.2022

Physics

$2.8\cdot 10^{-11} C$

Explanation:

The electric field produced by a point charge is given by

$E=k\frac{q}{r^2}$

where

k is the Coulomb's constant

q is the charge

r is the distance from the charge

In this problem, we have

E=100.0 N/C is the strength of the electric field

r=5.0 cm=0.05 m is the distance from the charge source of the field

Solving the formula for q, we find

$q=\frac{Er^2}{k}=\frac{(100 N/C)(0.05 m)^2}{9\cdot 10^9 Nm^2C^{-2}}=2.8\cdot 10^{-11} C$

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devinblitz4363

23.04.2020

Physics

can't stop the traffic light at the it travels along a straight road so that its distance should be calculated in a stand-in is velocity of the ka time is given 10 seconds how long after starting from rest is the car again at rest for the acceleration is equal to velocity initial final velocity - initial velocity divided by the total time taken just do it and see ok

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The strength of an electric field at 5.0 cm from a point charge is 100.0 n/c. what is the magnitude of the source charge? show your work.

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