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amandaparrish2323
17.02.2020 •
Physics
The Sun being a nuclear reactor furnace throws a variety of radiation at the Earth 1a. What types of radiation does it emit and in what proportion? 2. How do plants respond to the Sun’s frequencies? 3. What is the solar wind? 3a. in what manner does the solar wind interact with the Earth? 4. What are the nature of solar flares and what happens if the Earth is hit by a solar flare? 5. Does the Earth have any protection from the sun’s radiation? what might it be? how does it work? 6. What is an Aurora – and how are they created? 7. Is the Earth the only planet to have auroras? 8. What Solar event interacted with the Earth in August of 1859 - What was the consequence? 8a. What would be the outcome (consequences) if a similar event oc
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Ответ:
A) q = 5.714 × 10^(13) C
B) Because from a above, F_e = F_g and so r² canceled out in the formulas
C) m_t = 5.964 × 10⁴ kg
Explanation:
For the gravitational attraction of the earth and moon to be neutralized, the electrostatic force must be equal to the gravitational force i.e F_e = F_g
Now, F_e = kq²/r² and F_g = GmM/r²
Equating them and making q the subject, we arrive at;
q = √(GmM/k)
Where;
G is gravitational constant = 6.67 × 10^(-11) m³/kg.s²
m is mass of moon = 7.36 × 10^(22) kg
M is mass of earth = 5.98 × 10^(24) kg
k is coulombs constant = 8.99 x 10^(9) N.m²/c²
q = √(6.67 × 10^(-11) × 7.36 × 10^(22) × 5.98 × 10^(24)/8.99 x 10^(9))
q = 5.714 × 10^(13) C
B) We don't need the lunar distance because from a above, F_e = F_g and so r² canceled out in the formulas.
C) The number of protons is given by the formula;
n = q/e
Where, e is charge of the proton = 1.6 × 10^(-19) C
n = (5.714 × 10^(13))/(1.6 × 10^(-19))
n = 3.57125 × 10^(32)
Total mass of these protons is given by the formula;
m_t = nm_p
Where m_p is mass of a single proton = 1.67 × 10^(-27) kg
m_t = 3.57125 × 10^(32) × 1.67 × 10^(-27)
m_t = 5.964 × 10⁴ kg