Physics: The total electromagnetic power emitted by the sun is 3.8 × 1026 w. what is the radiation pressure on a totally absorbing satellite at the orbit of mercury, which has an orbital radius of 5.8 × 1010 m?

cExplanation:add together 10 and 5 and subtract that by 7 it s going down...

The total electromagnetic power emitted by the

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11.03.2022

$3.0\cdot 10^{-5} N/m^2$

Explanation:

The intensity of the radiation at the location of the satellite is given by:

$I=\frac{P}{4\pi r^2}$

where

$P=3.8\cdot 10^{26}W$ is the power of the emitted radiation

$4\pi r^2$ is the area over which the radiation is emitted (the surface of a sphere), with

$r=5.8\cdot 10^{10}m$ being the radius of the orbit

Substituting,

$I=\frac{3.8\cdot 10^{26}}{4\pi (5.8\cdot 10^{10})^2}=8989 W/m^2$

Now we can find the pressure of radiation, that for a totally absorbing surface (such as the satellite) is:

$p=\frac{I}{c}$

where

$c=3.0\cdot 10^8 m/s$

is the speed of light. Substituting,

$p=\frac{8989}{3.0\cdot 10^8}=3.0\cdot 10^{-5} N/m^2$

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