Physics: The wavelength of light emitted by a particular laser is 477 nm. this laser light illuminates two slits that are 54.0 µm apart, and a screen is 1.40 m from the slits. what is the angular separation between the n = 2 and n = ? 2 maxima?

The answer should be d because they are constantly rotating...

The wavelength of light emitted by a particular

MysteryDove12

12.01.2022

The angular separation is 2.024°.

Explanation:

Given that,

Wavelength = 477 nm

Distance of two slits d= 54.0 μm

Distance from screen = 1.40 m

We need to calculate the angular separation

Using formula of angular separation

$\sin\theta= n\lambda$

Where, d = distance

$\lambda$ = wavelength

Put the value into the formula

$\sin\theta=\dfrac{n\lambda}{2d}$

$\theta=\sin^{-1}(\dfrac{2\times477\times10^{-9}}{54.0\times10^{-6}})$

$\theta=1.012^{\circ}$

The angular separation is

$angular\ separation =2\theta$

Put the value into the formula

$angular\ separation =2\times1.012$

$angular\ separation =2.024^{\circ}$

Hence, The angular separation is 2.024°.

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