mmlordpepe9256

13.03.2020 • 

Physics

To understand how to calculate capacitance, voltage, and charge for a combination of capacitors connected in series.Consider the combination of capacitors shown in the figure.(Figure 1) Three capacitors are connected to each other in series, and then to the battery. The values of the capacitances are C, 2C, and 3C, and the applied voltage is ?V. Initially, all of the capacitors are completely discharged; after the battery is connected, the charge on plate 1 is QPart AWhat are the charges on plates 3 and 6?a. +Q and +Qb. ?Q and ?Qc. +Q and ?Qd. ?Q and +Qe. 0 and +Qf. 0 and ?Q

Ответ:

reaganphelps3

02.11.2022

Physics

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Work done = change in kinetic energy of vehicle

k.e. = ½mv²

So the k.e. of the vehicle changes from (½ * 1600 * 15.0²) = 180000 joules

to (½ * 1600 * 40.0²) = 1280000

That is an increase of (1280000 - 180000) = 1100000 joules = 1100 kJ

Power = energy / time

To supply that 1100 kJ of energy in 4.00 s therefore requires a net power of

(1100 kJ / 4.00 s) = 275 kW

Explanation:

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