![Savagepanda911](/avatars/49902.jpg)
Savagepanda911
01.04.2020 •
Physics
Two loudspeakers are placed at either end of a gymnasium, both pointing toward the center of the gym and equidistant from it. The speakers emit 296 Hz sound that is in phase. An observer at the center of the gym experiences constructive interference.How far toward either speaker must the observer walk to first experience destructive interference?
Solved
Show answers
More tips
- S Society and Politics What Would Brezhnev Do If He Were Alive Today?...
- S Style and Beauty Choosing a Hair Straightener: Specific Criteria to Consider...
- F Family and Home How to Remove Tar Stains: Tips and Recommendations from Experts...
- F Family and Home How to Remove Fading from Clothes: Tips and Tricks...
- S Sport How to Do a Jumping Split...
- H Health and Medicine How Did Inna Lose Weight on Dom 2?...
- F Family and Home How to Properly Fold Napkins in a Napkin Holder?...
- F Food and Cooking How to Set Up Ventrilo - The Ultimate Guide...
- S Science and Technology How to Make a Homemade Smoker: The Ultimate Guide...
- A Auto and Moto Battle for the Relocation of The Cherkizovsky Market: Who Won?...
Answers on questions: Physics
- M Mathematics A one-gallon can of paint costs $9.92. A five-gallon can of paint costs $43.29. How much will someone save if they buy the five-gallon can rather than five one-gallon...
- E English Explain how today society has some differences and similarities to the society on the farm (animal farm- george orwell)...
- M Mathematics A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection across the followed by a translation...
Ответ:
The observer must walk 0.2897m towards either speaker.
Explanation:
Let us make distance between the two speakers to be =D
frequency emitted by the two speakers in phase=f
v= speed of sound, 343 m/s
λ=wavelength
solving for λ, wavelength, using the equation λ=v/f. 343/296
= 1.15878m
Also destructive interference is given as
⎮d1-d2⎮=λ/2
Because the observer should be able to walk far enough to make the distance to one speaker differ from the distance to the other speaker by ½ wavelength.
This will give us
d1-d2= 1.15878 /2
d1-d2=0.5794m
For the distance moved on either side, we have D/2
Therefore 0.5794/2=distance to move on either side. Giving us
0.2897m
In conclusion, This means that the observer has to walk so as to be 0.5794m closer to one speaker from another; this means walking 0.2897m towards either speaker.
Ответ:
so, 1/4