Lovebamagirl12
02.07.2020 •
Physics
Un proyectil es disparado horizontalmente con una angulo de tiro de 30 grados y una velocidad inicial de 850 metros por segundo. Calcular El tiempo de vuelo, altura máxima, alcance horizontal, posición a los 25 segundos, velocidad resultante a los 25 segundos
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Ответ:
A) 86.7s
B) 9,215.56m
C) 63821.74m
D) 18402.5m
E) 757.79m/s
Explanation:
Given the following :
Angle of projection (Θ) = 30°
Initial Velocity (u) = 850m/s
g = acceleration due to gravity = 9.8m/s^2
A) The time of flight (T)
(2 × u × SinΘ) / g
(2 × 850 × sin30) / 9.8
(2 × 850 × 0.5) / 9.8
= 850 / 9.8 = 86.7seconds
B) Maximum height(H)
H = (u^2 × sin^2Θ) / 2g
H = (850^2 × 0.5^2) / 2 × 9.8
H = 180,625 / 19.6
H = 9215.5612m = 9,215.56m
C) horizontal range :
u × cosΘ × Time of fligt(T)
850 × cos30 × 86.7
850 × 0.866 × 86.7
= 63821.742m
D) position at 25 seconds
Distance = Speed × time
Distance at 25s = u × cosΘ × 25
= 850 × 0.866 × 25
= 18402.5m
E) Resulting Speed at 25s
Speed = distance / time
18402.5 / 25
Horizontal = 736.1 m/s
Vertical speed:
v = u + at
v = 850(sin30) + (-9.8 × 25)
v = 425 - 245
v = 180 m/s
Resulting speed :
V = √180^2 + 736.1^2
V = 757.78836m/s
Ответ:
length
Explanation:
hope it's helpful to you
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