What is the de Broglie wavelength (in nanometers) associated with a 2.70−g Ping-Pong ball traveling at 15.3 mph? Enter your answer in scientific notation.
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Ответ:
λ = 3.588 x 10^-44 nm
Explanation:
λ = h / m v
Where λ is the de Brogile wavelength
m = 2.70g, v = 15.3 mph = 6.839712 ms^-1
λ = 6.626 x 10^-34 / 2.70 x 6.839712 = 3.588 x 10^-44 nm
Ответ:
feed it to a spider
Explanation:
LMAO