Physics: What is the density of a cube of iron that is 3 inches on each side and has a mass of 13g?

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What is the density of a cube of iron that is 3 inches

meandmycousinmagic

04.02.2022

$\boxed {\tt 0.481481481 \ g/in^3}$

Explanation:

Density can be found by dividing the mass by the volume.

$d=\frac{m}{v}$

The mass is 13 grams. Let's calculate the volume. This is a cube, so the volume formula is:

v=s³The side length (s) is 3 inches v=(3 in)³= 3 in * 3 in * 3in = 27 in³

The volume is 27 cubic inches.

$m= 13 \ g\\v= 27 \ in^3$

Substitute the values into the formula.

$d=\frac{13 \ g}{27 \ in^3}$

Divide.

$d=0.481481481 \ g/in^3$

The density is 0.481481481 grams per cubic inch.

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