Physics: Which describes the electric forces inside an atom? a. gravitational forces are much stronger than electric forces. b. electric forces and gravitational forces are equal in this setting. c. electric forces are much stronger than gravitational forces.

Explanation:The mass of the load isAs the mass hangs, the cables must be tight, so, we can obtain the vector parallel to the cable as:where is the position of the load and is the point where the cable is anchored. So, for our cablesWe know that the forces must be in this directions, so we can writeWe also know, as the system is in equilibrium, the sum of the forces must be zero:where is the weight,So, we get:This gives us the following equations:From equation [2] is clear that , we can see thatNow,...

Which describes the electric forces inside an

Ответ:

beverly3966

06.07.2021

Physics

$\vec{F}_{cable_1} = (-19.245 \ lbf ,0, 33.333 \ lbf)$ $\vec{F}_{cable_2} = (9.622 \ lbf , 13.608 \ lbf ,33.333 \ lbf)$ $\vec{F}_{cable_3} = (9.622 \ lbf , -13.608 \ lbf ,33.333 \ lbf)$

Explanation:

The mass of the load is

$m_{load} = 100 \ lb$

As the mass hangs, the cables must be tight, so, we can obtain the vector parallel to the cable as:

$\vec{r}_{cable} = \vec{r}_{anchored} - \vec{r}_{load}$

where $\vec{r}_{load}$ is the position of the load and $\vec{r}_{anchored}$ is the point where the cable is anchored.

So, for our cables

$\vec{r}_{cable_1} = (-4,0,0) - (0,0,-4\sqrt{3})=(-4,0,4\sqrt{3})$

$\vec{r}_{cable_2} = (2,2\sqrt{3},0) - (0,0,-4\sqrt{3})=(2,2\sqrt{2},4\sqrt{3})$

$\vec{r}_{cable_3} = (2,-2\sqrt{3},0) - (0,0,-4\sqrt{3})=(2,-2\sqrt{2},4\sqrt{3})$

We know that the forces must be in this directions, so we can write

$\vec{F}_i=k_i \vec{r}_{cable_i}$

We also know, as the system is in equilibrium, the sum of the forces must be zero:

$\vec{F}_{cable_1}+\vec{F}_{cable_2}+\vec{F}_{cable_3}+\vec{W}=0$

where $\vec{W}$ is the weight,

$\vec{W} = (0,0,-100 \ lbf)$

So, we get:

$k_1 (-4,0,4\sqrt{3}) + k_2 (2,2\sqrt{2},4\sqrt{3}) + k_3 (2,-2\sqrt{2},4\sqrt{3}) + (0,0,-100 \ lbf) = (0,0,0)$

This gives us the following equations:

$-4 \ k_1 + 2 \ k_2 + 2 \ k_3 = 0$ $2\sqrt{2} \ k_2 -2\sqrt{2} \ k_3 = 0$ $4\sqrt{3} \ k_1 + 4\sqrt{3} \ k_2 + 4\sqrt{3} \ k_3 -100 \ lbf = 0$

From equation [2] is clear that k_2 = k_3 , we can see that

$2\sqrt{2} \ k_2 = 2\sqrt{2} \ k_3$

$\frac{2\sqrt{2} \ k_2}{2\sqrt{2} } = \frac{2\sqrt{2} \ k_3}{2\sqrt{2} }$

k_2 = k_3

Now, putting this in equation [1]

$-4 \ k_1 + 2 \ k_2 + 2 \ k_3 = -4 \ k_1 + 2 \ k_3 + 2 \ k_3 = -4 \ k_1 + 4 \ k_3 = 0$

$4 \ k_1 = 4 \ k_3$

$\ k_1 = \ k_3$

Taking this result to the equation [3]

$4\sqrt{3} \ k_1 + 4\sqrt{3} \ k_2 + 4\sqrt{3} \ k_3 -100 \ lbf = 0$

$4\sqrt{3} \ k_3 + 4\sqrt{3} \ k_3 + 4\sqrt{3} \ k_3 = 100 \ lbf$

$3 * (4\sqrt{3} \ k_3) = 100 \ lbf$

$k_3 = \frac{100 \ lbf}{ 12 \sqrt{3}}$

$k_1 = k_2 = k_3 = \frac{100 \ lbf}{ 12 \sqrt{3}}$

So, the forces are:

$\vec{F}_{cable_1} = k_1 (-4,0,4\sqrt{3})$

$\vec{F}_{cable_1} = \frac{100 \ lbf}{ 12 \sqrt{3}} (-4,0,4\sqrt{3})$

$\vec{F}_{cable_1} = (-\frac{100 \ lbf}{ 3 \sqrt{3}},0,\frac{100 \ lbf}{3})$

$\vec{F}_{cable_1} = (-19.245 \ lbf ,0, 33.333 \ lbf)$

$\vec{F}_{cable_2} = k_2 (2,2\sqrt{2},4\sqrt{3})$

$\vec{F}_{cable_2} = \frac{100 \ lbf}{ 12 \sqrt{3}} (2,2\sqrt{2},4\sqrt{3})$

$\vec{F}_{cable_2} = (9.622 \ lbf , 13.608 \ lbf ,33.333 \ lbf)$

$\vec{F}_{cable_3} = k_3 (2,-2\sqrt{2},4\sqrt{3})$

$\vec{F}_{cable_3} = \frac{100 \ lbf}{ 12 \sqrt{3}} (2,-2\sqrt{2},4\sqrt{3})$

$\vec{F}_{cable_3} = (9.622 \ lbf , -13.608 \ lbf ,33.333 \ lbf)$

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Which describes the electric forces inside an atom?

a. gravitational forces are much stronger than electric forces.

b. electric forces and gravitational forces are equal in this setting.

c. electric forces are much stronger than gravitational forces.

Ответ:

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