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zamorano2339
12.03.2022 •
Physics
Which turbine takes the lesser amount of time to rotate through 1. 0 radian of angular displacement?.
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Ответ:
The speed is 49 cm/s
Explanation:
Given;
mass of the object, m = 0.20 kg
spring constant, k = 10 N/m
amplitude, A = 0.080 m
Total energy of the spring = ¹/₂kA² = ¹/₂ x 10 x (0.08)²
Total energy of the spring = 0.032 J
When its displacement is 0.040 m = half of Amplitude
Applying conservation of energy
Total energy of the spring = PE + KE
0.032 = ¹/₂kA² + ¹/₂mv²
0.032 = ¹/₂ x 10 x (0.04)² + ¹/₂ x 0.2 x v²
0.032 = 0.008 + 0.1v²
0.1v² = 0.032 - 0.008
0.1v² = 0.024
v² = 0.24
v = √0.24
v = 0.49 m/s = 49 cm/s
Therefore, the speed is 49 cm/s