Physics: Would anyone pls me on these questions

Would anyone pls me on these questions

phy75

12.06.2020

(a) 40.3 Nm

When a force is applied perpendicular to the door, the magnitude of the torque exerted by the person is given by

$\tau = F d$

where

F = 42 N is the magnitude of the force

d = 96 cm = 0.96 m is the distance between the point of application of the force and the centre of rotation of the door

Substituting numbers into the formula, we find

$\tau = (42 N)(0.96 m)=40.3 Nm$

(b) 34.9 Nm

In this case, the force is no longer perpendicular to the door, so we must use the formula for the general case:

$\tau = Fd sin \theta$

where

$\theta = 60^{\circ}$ is the angle between the direction of the force and the face of the door

Substituting numbers into the formula, we find

$\tau=(42 N)(0.96 m)(sin 60^{\circ})=34.9 Nm$

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