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makiyabattles
22.11.2020 •
Physics
You are piloting a helicopter which is rising vertically at a uniform velocity of 14.70 m/s. When you reach 196.00 m, you see Barney (Uh-oh). A large object is projected with a horizontal velocity of 8.50 m/s from the rising helicopter. When does the ball reach Barney's head if he is standing in a hole with his head at ground level?
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Ответ:
The ball reaches Barney head in![t = 8 \ s](/tpl/images/0922/1295/4c68b.png)
Explanation:
From the question we are told that
The rise velocity is![v = 14.70 \ m/s](/tpl/images/0922/1295/9757d.png)
The height considered is![h = 196 \ m](/tpl/images/0922/1295/44b12.png)
The horizontal velocity of the large object is![v_h = 8.50 \ m/s](/tpl/images/0922/1295/07045.png)
Generally from kinematic equation
Here s is the distance of the object from Barney head ,
u is the velocity of the object along the vertical axis which is equal but opposite to the velocity of the helicopter
So
So
=![4.9 t^2 - 14.7t - 196 = 0](/tpl/images/0922/1295/15f6d.png)
Solving the above equation using quadratic formula
The value of t obtained is![t = 8 \ s](/tpl/images/0922/1295/4c68b.png)
Ответ:
potential energy and kinetic idk ur question
Explanation:
idk