You stand on a bridge above a river and drop a rock into the water below from a height of 25 m. (assume no air resistance)
a. what is the acceleration of the rock as it falls?
b. how long does it take to hit the water?
c. how much more time would it take if instead of dropping the rock straight down you threw horizontally with a speed of 20 m/s?
d. you throw another rock at an angle of 65 degrees above the horizontal with a speed of 20 m/s. what are the x- and y- components of the rock's speed?
e. how long does it take the rock to reach its maximum height?
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Ответ:
PART a)
here when stone is dropped there is only gravitational force on it
so its acceleration is only due to gravity
so we will have
Part b)
Now from kinematics equation we will have
now we have
y = 25 m
so from above equation
Part c)
If we throw the rock horizontally by speed 20 m/s
then in this case there is no change in the vertical velocity
so it will take same time to reach the water surface as it took initially
So t = 2.26 s
Part D)
Initial speed = 20 m/s
angle of projection = 65 degree
now we have
PART E)
when stone will reach to maximum height then we know that its final speed in y direction becomes zero
so here we can use kinematics in Y direction
so it will take 1.85 s to reach the top
Ответ:
All of those are things they need to have on the label
Explanation:
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