Biology: An open system in which the growth rate of microorganisms is maintained by adding a nutrient (present in limiting quantities) at the same rate that medium containing microorganisms is removed is called

An open system in which the growth rate of microorganisms

bob7220

01.04.2020

The average time that it takes for the car to travel the first 0.25m is 2.23 s

The average time that it takes for the car to travel the first 0.25 m is given by:

$t=\frac{2.24 s+2.21 s+2.23 s}{3}=2.227 s \sim 2.23 s$

The average time to travel just between 0.25 m and 0.50 m is 0.90 s

First of all, we need to calculate the time the car takes in each trial to travel between 0.25 m and 0.50 m:

$t_1 = 3.16 s - 2.24 s=0.92 s\\t_2 = 3.08 s- 2.21 s=0.87 s\\t_3 =3.15 s- 2.23 s=0.92 s$

Then, the average time can be calculated as

$t=\frac{0.92 s+0.87 s+0.92 s}{3}=0.90 s$

Given the time taken to travel the second 0.25 m section, the velocity would be 0.28 m/s

The velocity of the car while travelling the second 0.25 m section is equal to the distance covered (0.25 m) divided by the average time (0.90 s):

$v=\frac{d}{t}=\frac{0.25 m}{0.90 s}=0.28 m/s$

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