Help please someone please what is the answer

Explanation:

Both parents have black color and normal vision but some of their progenies show brown color and some shows PRA, this reveals the brown coat color and PRA are recessive traits and both parents are heterozygous. The progenies include black normal vision, brown normal vision and black, PRA, that is the alleles for these genes separate independently of each other.

Let us denote the alleles as B-black, b-brown and P-normal vision, p-PRA, then the genotype of the heterozygous parent is BbPp, alleles separate independently of each other so the possible gametes are alleles for the color and vision segregate independently during gamete formation.

Thus, option C is correct.