In the absence of recombination, how many genetically different types of gamete can an organism with six homologous chromosome pairs produce?
a) 6
b) 12
c) 36
d) 64
e) none of the above
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Ответ:
(D) 64
Explanation:
We have given number of chromosome pair that is haploid number = 6
We have to calculate the number of possible gamete in absence of recombination
The number of garnets is given by
where n is haploid number
In question we have given haploid number, that is n=6
So the number of gametes without recombination![=2^6=64](/tpl/images/0212/5146/97b30.png)
So option (d) is the correct answer
Ответ: