The genetic frequencies of two separate populations are: aa aa aa population 1 .36 .48 .16 population 2 .55 .10 .35 a) what are the genotypic frequencies of the two populations? b) what are the allele frequencies? c) are the populations in hardy-weinberg equilibrium?
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Ответ:
Explanation:
first solve for genetic frequency
Population 1
genetic frequency AA = 36/100 = 0.36
Aa = 48/100 = 0.48
aa = 16/100 = 0.16
Allele frequency
A = 0.36 + (0.5 x 0.48) = 0.60
a = 0.16 + (0.5 x 0.48) = 0.40
Population 2
genetic frequency AA = 55/100 = 0.55
Aa = 10/100 = 0.10
aa = 35/100 = 0.35
allele frequency
A = 0.55 + (0.5 x 0.10) = 0.60
a = 0.35 + (0.5 x 0.10) = 0.40
Weinberg equilibrium states that the allele frequency of a population will remain the same from generation to generation or else there is a catastrophic activity.
from the calculations above, assuming population 1 and 2 are two different generations, it is perfectly in Weinberg equilibrium because the allele frequency is the same.
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