Biology: The surface area-to-volume ratio of cells determines how quickly they can absorb materials. suppose that a space mission to planet zognard-42 uncovers giant cube-shaped single celled organisms living in an oxygen atmosphere. one species of cube-shaped organism is 2 cm on each side. another is 1 cm on each side. about how much faster will the smaller cube organism be able to absorb oxygen? a) 2 times b) 3 times c) 6 times d) they will absorb at the same rate.

The surface area-to-volume ratio of cells determines

oscar3231

11.03.2022

species one has a sa of 24 (2*2*6) and a volume of 8 (2*2*2) so I'll make that a ratio of 1:3

species two has a sa of 6 (1*1*6) and a volume of 1 (1*1*1) so I'll make that a ratio of 1:6

2*3=6 so it will absorb oxygen twice as fast

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stodd9503

11.03.2022

Option , A Smaller species will absorb oxygen 2 times faster than the larger species.

Explanation:

The amount of material absorbed by cells is directly determined by the surface area-to-volume ratio of cells.

A)Species 1 is of cube shape with sides of 2 cm

B)Species 2 is of cube shape with sides of 1 cm

Now we will evaluate the surface area-to-volume ratio for both the species

1) Species 1 -

Volume of a cube is $a^{3}$

Surface area of a cube is $6a^{2}$

surface area-to-volume ratio $= \frac{6a^{2} }{a^{3} } \\= \frac{6}{a}$

Here

$a = 2 \\$

surface area-to-volume ratio for species 1 is $\frac{6}{2} \\= 3$

1) Species 2 -

Volume of a cube is $a^{3}$

Surface area of a cube is $6a^{2}$

surface area-to-volume ratio $= \frac{6a^{2} }{a^{3} } \\= \frac{6}{a}$

Here

$a = 1 \\$

surface area-to-volume ratio for species 1 is $\frac{6}{1} \\= 6$

Species 2 (the smaller one) will absorb oxygen 2 times faster than the larger species.

Hence, Option A is correct

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