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Skylar4483

Skylar4483

27.06.2019 •

Biology

Which is not a potential threat or danger to an ecosystem rich in biodiversity? a) deforestation b) plate tectonic activity c) global warming/climate change eliminate d) genetic diversity among species

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Ответ:

AariyahFennell

29.05.2020

The correct answer is option D, that is, genetic diversity among the species.

The sum of genetic characteristics in the genetic makeup of a species is known as genetic diversity. It is differentiated from genetic variability that illustrates the capability of genetic features to change.

The genetic diversity functions as a medium for the populations to amend with the fluctuating environments. With more changes, there is more possibility that some individuals in a population will exhibit different forms of alleles, which are appropriate for the surrounding.

These individuals hold high possibilities of survival in order to generate offspring exhibiting that allele. The population will continue for more generations due to the accomplishment of these individuals.

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Ответ:

henryzx900

22.12.2021

$\Rightarrow \frac{dh}{dt}\approx -31.690
$

Explanation:

The volume of a cone, V = 1/3πr^2h

Where r is the radius, and h is the height of the cone.

Given:

Volume is constant at 56 cubic feet.

Radius of cone increases at a constant rate of 8 feet per second.

The radius of the cone is 3 feet.

When radius is 3 feet

$\Rightarrow h= \frac{3V}{\pi r^2}$

$\Rightarrow h= \frac{3\times 56}{\pi \times 3^2}
$

$\Rightarrow h= \frac{3\times 56}{\pi \times 9}
$

$\Rightarrow h= \frac{ 56}{3\pi}
$

Where h is in feets.

$\frac{dV}{dt}=\frac{d (\frac{1}{3}\pi r^2h) }{dt}
$

$\Rightarrow \frac{dV}{dt}=(\frac{1}{3}\pi \frac{dr^2}{dt}h)+(\frac{1}{3}\pi r^2 \frac{dh}{dt})
$

$\Rightarrow \frac{dV}{dt}=(\frac{1}{3}\pi \frac{dr^2}{dr}.\frac{dr}{dt}h)+(\frac{1}{3}\pi r^2 \frac{dh}{dt})
$

$\Rightarrow \frac{dV}{dt}=(\frac{1}{3} \pi 2r\frac{dr}{dt}h)+(\frac{1}{3}\pi r^2 \frac{dh}{dt})
$

Since the volume is constant so $\frac{dV}{dt}=0
$

The rate of change of radius is $\frac{dr}{dt}=8
$

$\Rightarrow 0=(\frac{1}{3} \pi (2\times 3)(8)(\frac{56}{3\pi}))+(\frac{1}{3}\pi (3^2) \frac{dh}{dt})
$

$\Rightarrow 0=(\frac{56\times 16}{3})+(\frac{1}{3}\pi (9) \frac{dh}{dt})
$

$\Rightarrow 0=(\frac{56\times 16}{3})+(3\pi \frac{dh}{dt})
$

$\Rightarrow 3\pi \frac{dh}{dt}=-\frac{56\times 16}{3}
$

$\Rightarrow \frac{dh}{dt}=-\frac{56\times 16}{3\times 3 \times \pi}
$

$\Rightarrow \frac{dh}{dt}=-\frac{56\times 16}{9\pi}
$

$\Rightarrow \frac{dh}{dt}=-31.689518
$

$\Rightarrow \frac{dh}{dt}\approx -31.690
$

The minus indicates that the rate of change of height is decreasing.

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