2. suppose that 21.37 ml of naoh is needed to titrate 10.00 ml of 0.1450 m h2so4 solution.
(a) write a balanced reaction equation for the acid-base neutralization.
(b) calculate the molarity of naoh based on the results of this titration.

0.1357 M

Explanation:

(a) The balanced reaction is shown below as:

(b) Moles of can be calculated as:

Or,

Given :

For :

Molarity = 0.1450 M

Volume = 10.00 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 10×10⁻³ L

Thus, moles of :

Moles of  = 0.00145 moles

From the reaction,

1 mole of react with 2 moles of NaOH

0.00145 mole of react with 2*0.00145 mole of NaOH

Moles of NaOH = 0.0029 moles

Volume = 21.37 mL = 21.37×10⁻³ L

Molarity = Moles / Volume = 0.0029 /  21.37×10⁻³  M = 0.1357 M

False

Explanation:

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