Chemistry: (20 pts) When 3.018 moles of chlorine reacts with excess aluminum, how many moles of aluminum chloride are formed? 2 Al + 3 Cl2 → 2 AICI3:

(20 pts) When 3.018 moles of chlorine reacts with

Ответ:

TombRaider167

19.01.2022

Chemistry

$\large \boxed{\text{2.012 mol AlCl}_{3}}$

Explanation:

2Al + 3Cl₂ → 2AlCl₃

n/mol: 3.018

The molar ratio is 2 mol AlCl₃:3 mol Cl₂.

$\text{Moles of AlCl}_{3} = \text{ 3.018 mol Cl}_{2} \times \dfrac{\text{2 mol AlCl}_{3}}{\textbf{3 mol Cl}_{2}}\\\\= \text{2.012 mol AlCl}_{3}\\\text{The reaction produces $\large \boxed{\textbf{2.012 mol AlCl}_{3}}$}$

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Ответ:

annekesimonsen

28.04.2021

Chemistry

1. analyze the samples while they are frozen

stuff can react differently when it's colder

Explanation:

hope I could help good luck

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(20 pts) When 3.018 moles of chlorine reacts with excess aluminum, how many moles of
aluminum chloride are formed?
2 Al + 3 Cl2 → 2 AICI3:

Ответ:

Ответ:

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