22. a flask containing 450 ml of 0.50 m h2so4 was accidentally knocked to the floor. how many grams of nahco, do you need to put on the spill to neutralize the acid according to the following equation: h2so4(aq)+2 nahcos(aq) na,so(aq) +2 h20()+2 co2(g) d) 38 g a) 2.3 g b) 9.5 g c) 19 g
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Ответ:
The correct answer is Option D.
Explanation:
To calculate the moles of a solute, we use the equation:
We are given:
Volume of sulfuric acid = 450mL = 0.45 L (Conversion factor: 1 L = 1000 mL)
Molarity of the solution = 0.5 moles/ L
Putting values in above equation, we get:
For the given chemical reaction:
By Stoichiometry of the reaction:
1 mole of sulfuric acid reacts with 2 moles of sodium bicarbonate.
So, 0.225 moles of sulfuric acid will react with =
of sodium bicarbonate
To calculate the mass of sodium bicarbonate, we use the equation:
Moles of sodium bicarbonate = 0.45 moles
Molar mass of sodium bicarbonate = 84.007 g/mol
Putting values in above equation, we get:
Hence, the correct answer is Option D.
Ответ:
1 year- 1 mole
time in general- amount of matter
1 second- 1 atom/ particle