4) cisplatin, pt(nh3)2cl2, has been studied as an antitumor agent. it is synthesized as follows:
k ptclafaq) + 2nh3(aq) → pt(nh3)2cl2(s)
+ 2 kclag)
what mass of cisplatin can be produced from 100. g of kzptcle and excess ammonia?
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Ответ:
Mass of cisplatin = 72.32 g
Explanation:
Given data:
Mass of KPtCl = 100 g
Mass of Cisplatin = ?
Solution:
First of all we will write the balance chemical equation.
Chemical equation:
K₂PtCl₄ (aq) + 2NH₃(aq) → Pt(NH₃)₂Cl₂(s) + 2KCl (aq)
Number of moles of = mass / molar mass
Molar mass of K₂PtCl₄ = 39.0983 ×2 + 195.084 + 35.5× 4
Molar mass of K₂PtCl₄ = 415.284 g/mol
Number of moles of K₂PtCl₄ = 100 g / 415.284 g/mol
Number of moles of K₂PtCl₄ = 0.241 mol
Now we will compare the moles of K₂PtCl₄ with Cisplatin from balance chemical equation.
K₂PtCl₄ : Pt(NH₃)₂Cl₂
1 : 1
0.241 : 0.241
Ammonia is in excess so mass of cisplatin depend upon the K₂PtCl₄.
Mass of cisplatin:
Mass of cisplatin = Number of moles × Molar mass
Mass of cisplatin = 0.241 mol × 300.1 g/mol
Mass of cisplatin = 72.32 g
Ответ:
H2SiO3:
STOCK: Ácido trioxosilícico
SISTEMATICA: Trioxosilicato de hidrógeno
TRADICIONAL: Ácido metasilícico