4 NH3(g) + 5 O2(g) → 4 NO (g) + 6 H2O (g) Use the balanced equation above to calculate the number of moles of water vapor that
can be produced from 25.0 g of NH3 and excess oxygen gas.

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therealrg10

25.03.2020

Chemistry

79 total miles

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4 NH3(g) + 5 O2(g) → 4 NO (g) + 6 H2O (g) Use the balanced equation above to calculate the number of moles of water vapor that can be produced from 25.0 g of NH3 and excess oxygen gas.