A physician orders 0.6 L of an 8% (m/v) solution of a drug in aqueous solution. The pharmacy has 300 mL of a 10 % (m/v) solution of this drug on hand. What volume of this solution would be needed to prepare the prescriptio
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Ответ:
The volume of the solution the pharmacy needs to prepare the prescription is 480 mL
Explanation:
The volume of the drug the physician orders = 0.6 L = 600 mL
The concentration of the drug the physician ordered = 8% (m/v)
The volume of the drug the pharmacy has = 300 mL
The concentration of the drug the pharmacy has = 10% (m/v)
Therefore;
The mass of the drug the physician ordered, m₁ = 600 × 8% = 48 g
The mass of the drug the pharmacy has, m₂ = 300 × 10% = 30 g
The mass of the drug the pharmacy needs = 48 g - 30 g = 18 g
The volume of the solution that needs to be added, Vₐ = 18 g/(10%) = 180 mL
Therefore, the volume of the solution the pharmacy needs to prepare the prescription, 'V', is given as follows;
V = Vₐ + 300 mL
V = 180 mL + 300 mL = 480 mL
The volume of the solution the pharmacy needs to prepare the prescription, V = 480 mL
Ответ:
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