A solution is prepared by mixing 50.0 mL of ethanol with 300.0 mL of water. What is the volume percent of ethanol in this solution? Assume volumes are additive.

The answer to your question is 14.3 %

Explanation:

Data

volume of ethanol = 50 ml

volume of water = 300 ml

volume percent = ?

Formula

Percent by volume = (volume of solute/volume of solution) x 100

Volume of solute = 50 ml

volume of solution = 300 + 50 = 350

Substitution

Percent by volume = (50/350) x 100

Simplification and result

Percent by volume = 14.3 %

The number of boys in the class is 12

The number of girls in the class is 20

Step-by-step explanation:

Given as :

The ratio of boys to girls in school classroom = 3 : 5

The Total number of students in class = 32

Let The number of boys in class = 3 x

And The number of girls in class = 5 x

According to question

The Total number of students in class = The number of boys in class + The number of girls in class

Or, 3 x + 5 x = 32

Or, 8 x = 32

∴   x =

I.e x = 4

So, The number of boys in class = 3 x = 3 ×4 = 12

And The number of girls in class = 5 x = 5 ×4 = 20

Hence The number of boys in the class is 12

And The number of girls in the class is 20   Answer