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annapittbull12
20.09.2019 •
Chemistry
A25-ml sample of 0.160m solution of naoh is titrated with 17 ml of an unknown solution of
h2
so4
. what is the molarity of the sulfuric acid solution?
a. 0.235m h2
so4
b. 0.117m h2so4
c. 0.004m h2
so4
d. 0.002m h2so4
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Ответ:
M ( NaOH ) = 0.160 M
V ( H2SO4) = 17 mL / 1000 => 0.017 L
M ( H2SO4) = ?
number of moles NaOH:
n = M x V = 0.160 x 0.025 => 0.004 moles NaOH
Mole ratio :
2 NaOH + H2SO4 = Na2SO4 + 2 H2O
2 moles NaOH 1 mole H2SO4
0.004 moles NaOH ? moles H2SO4
moles H2SO4 = 0.004 x 1 / 2
= 0.002 moles of H2SO4
M ( H2SO4) = n / V
M = 0.002 / 0.017
= 0.117 M H2SO4
Answer B
hope this helps!
Ответ:
Hyrdrogen monobromide is : HBr
Hope this helped :)