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aliami0306oyaj0n
16.01.2020 •
Chemistry
Achemist prepares a solution of copper(ii) fluoride (cuf2) by measuring out 0.032 µmol of copper(ii) fluoride into a 500 ml volumetric flask and filling the flask to the mark with water.calculate the concentration in mol/l of the chemist's copper(ii) fluoride solution.
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Ответ:
Answer : The concentration of copper(II) fluoride in the solution is,![6.4\times 10^{-8}mole/L](/tpl/images/0458/0284/bae7a.png)
Explanation : Given,
Moles of copper(II) fluoride = 0.032 μ
mol =![0.032\times 10^{-6}mol=3.2\times 10^{-8}mol](/tpl/images/0458/0284/2cfa2.png)
conversion used :![\mu mol=10^{-6}mol](/tpl/images/0458/0284/d23ea.png)
Volume of solution = 500 mL
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Now put all the given values in this formula, we get:
Therefore, the concentration of copper(II) fluoride in the solution is,![6.4\times 10^{-8}mole/L](/tpl/images/0458/0284/bae7a.png)
Ответ:
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Explanation: