Chemistry: Amixture of he, ne, and n2 gases are a pressure of 1.348. if the pressures of he and ne are 0.124 atm, what is the partial pressure of n2 in the mixture ?

Amixture of he, ne, and n2 gases are a pressure of

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12.03.2022

Answer : The partial pressure of N_2 in the mixture is, 1.224 atm

Solution :

According to the Dalton's law, the total pressure of the gas is equal to the sum of the partial pressure of the mixture of gasses.

$P_T=p_{He}+p_{Ne}+p_{N_2}$

where,

P_T = total partial pressure of $He,Ne\text{ and }N_2$ = 1.348 atm

$P_{He}$ = partial pressure of helium

$P_{Ne}$ = partial pressure of neon

$P_{N_2}$ = partial pressure of nitrogen

As we are given that,

$P_{He}+P_{Ne}=0.124atm$

Now put all the given values in above expression, we get the partial pressure of the nitrogen gas in the mixture.

$1.348atm=0.124atm+p_{N_2}$

$p_{N_2}=1.224atm$

Therefore, the partial pressure of N_2 in the mixture is, 66 Kpa

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