An aqueous solution of perchloric acid is standardized by titration with a 0.175 M solution of barium hydroxide. If 26.0 mL of base are required to neutralize 25.4 mL of the acid, what is the molarity of the perchloric acid solution?

If the voltage of circuit A is equal to the voltage of circuit B, then the current in circuit A is less than the current in circuit B

Explanation:

To know the the correct answer to the question, do the following:

Case 1: Let the circuit A and B have equal voltage say 24 V.

For Circuit A:

Voltage (V) = 24 V

Resistance (R) = 7.5 ohms

Current (I) =?

V = IR

24 = I × 7.5

Divide both side by 7.5

I = 24 / 7.5

I = 3.2 A

For Circuit B:

Voltage (V) = 24 V

Resistance (R) = 5 ohms

Current (I) =?

V = IR

24 = I × 5

Divide both side by 5

I = 24 / 5

I = 4.8 A

Thus for the same voltage, current in circuit A is less than the current in B.

Case 2: Let circuit A and B have equal current say 2 A

For circuit A:

Current (I) = 2 A

Resistance (R) = 7.5 ohms

Voltage (V) =?

V = IR

V = 2 × 7.5

V = 15 V

For Circuit B:

Current (I) = 2 A

Resistance (R) = 5 ohms

Voltage (V) =?

V = IR

V = 2 × 5

V = 10 V

Thus, for the same current, the voltage in circuit A is greater than the voltage in B

Case 3: Let circuit A have a current of 4 A and circuit B have a current of 5 A

For circuit A:

Current (I) = 4 A

Resistance (R) = 7.5 ohms

Voltage (V) =?

V = IR

V = 4 × 7.5

V = 30 V

For circuit B:

Current (I) = 5 A

Resistance (R) = 5 ohms

Voltage (V) =?

V = IR

V = 5 × 5

V = 25 V

Thus, when the current in circuit A is less than the current in circuit B, the voltage in circuit A is greater than the voltage in circuit B.

From the illustrations above and the options given in the question, the current answer is:

If the voltage of circuit A is equal to the voltage of circuit B, then the current in circuit A is less than the current in circuit B