lexilove262
06.10.2019 •
Chemistry
An electron in the n=6 level of the hydrogen atom relaxes to a lower energy level, emitting light of ? =93.8nm. find the principal level to which the electron relaxed.
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Ответ:
We can find the principal level or lower level using Rydberg's formula:
1/w = R(1/L² - 1/U²)
where:
w is the wavelength (93.8 nm),
L is the lower energy level (unknown)
U the upper energy level (n= 6)
R is Rydberg's constant (10,967,758 waves per meter)
Substituing known values into the equation:
1/(9.38 * 10^-8 m.) = 10,967,758(1/L² - 1-36)
Using the solver function of the calculator to get for L:
L = 0.999
so L = 1.
The lower level is 1 (the ground state).
Ответ:
pH=14-pOH
pOH=-lg[OH⁻]
pH=14+lg[OH⁻]
pH=14+lg0.010=14-2=12
pH=12