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18.01.2020 •
Chemistry
Approximately how many moles of al3+ are reduced when 0.1 faraday of charge passes through a cell during the production of al? (note: assume there is excess al3+ available and that al3+ is reduced to al metal only.)
a. 0.033 molb. 0.050 molc. 0.067 mold. 0.10 mol
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Ответ:
0.033 mol
Explanation:
1 faraday is require to 1 mol of electron
0.1 faraday is required for 0.1 mol of electron
3 mol of electron is required for 1 mole Al3+ to Al
0.1 mole of electron will therefore need ( 0.1 mol × 1 mol ) / 3 mol = 0.033 mol
Ответ:
So, the answer is B mixture called a solution.