Astudent wants to make a 0.150 m aqueous solution of silver nitrate, agno3, and has a bottle containing 11.27 g of silver nitrate. what should be the final volume of the solution

V = 0.44 L

Explanation:

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

w = 11.27 g

m ( for AgNO₃ ) =  169.87 g/mol

Hence , the moles can be calculated as -

n = w / m

n = 11.27 g / 169.87 g/mol

n = 0.066 mol

Molarity -

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

From the question ,

M = 0.150 M

n = 0.066 mol ( calculated above )

The final volume of the solution can be calculated by using the above equation ,

M = n / V  

0.150 M = 0.066 mol / V

V = 0.44 L

The electron configuration of an excited atom that is likely to emit a quantum of energy is 1s2 2s2 2p6 3s1 3p1.

The lowest energy configuration of electrons in an atom is usually referred to as its ground state.

Higher energy levels are referred to as excited states. The excited state of an atom s likely to emit a quantum of energy.

If we look at the configuration; 1s2 2s2 2p6 3s1 3p1, we can see that it corresponds to an excited state. A 3s electron has been promoted to the 3p level.

This configuration  is likely to emit a quantum of energy

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