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fendyli1529
14.07.2019 •
Chemistry
At 25.0°c, a solution has a concentration of 3.179 m and a density of 1.260 g/ml. the density of the solution at 50.0°c is 1.249 g/ml. what is the molarity of the solution at 50.0 °c?
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Ответ:
-
3.151 M
Explanation: -
Let the volume of the solution be 1000 mL.
At 25.0 °C, Density = 1.260 g/ mL
Mass of the solution = Density x volume
= 1.260 g / mL x 1000 mL
= 1260 g
At 25.0 °C, the molarity = 3.179 M
Number of moles present per 1000 mL = 3.179 mol
Strength of the solution in g / mol
= 1260 g / 3.179 mol = 396.35 g / mol (at 25.0 °C)
Now at 50.0 °C
The density is 1.249 g/ mL
Mass of the solution = density x volume = 1.249 g / mL x 1000 mL
= 1249 g.
Number of moles present in 1249 g = Mass of the solution / Strength in g /mol
=![\frac{1249 g}{396.35 g/mol}](/tpl/images/0086/7911/c1083.png)
= 3.151 moles.
So 3.151 moles is present in 1000 mL at 50.0 °C
Molarity at 50.0 °C = 3.151 M
Ответ:
The answer to your question is below
Explanation:
Data
Aqueous sodium carbonate = Na₂CO₃ (aq)
Aqueous strontium chloride = SrCl₂ (aq)
Solid strontium carbonate = SrCO₃ (s)
Aqueous sodium chloride = NaCl (aq)
Unbalnced Chemical reaction
Na₂CO₃(aq) + SrCl₂(aq) ⇒ SrCO₃(s) + NaCl(aq)
Reactants Elements Products
2 Sodium 1
1 Carbon 1
1 Strontium 1
2 Chlorine 1
3 Oxygen 3
Balanced Chemical reaction
Na₂CO₃(aq) + SrCl₂(aq) ⇒ SrCO₃(s) + 2NaCl(aq)
Reactants Elements Products
2 Sodium 2
1 Carbon 1
1 Strontium 1
2 Chlorine 2
3 Oxygen 3