At a certain temperature, 0.740 mol of so3 is placed in a 4.00 l container. so_{3}(g)\rightleftharpoons 2so_{2}(g)+o_{2}(g) at equilibruim, 0.190 mol of o2 is present. calculate kc.
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Ответ:
Answer : The equilibrium constant kc is 4.76 x 10⁻³
Explanation :
The given equilibrium reaction is
Step 1 : Set up ICE table
Let us set up an ICE table for this reaction .
The initial concentration of SO₃ is
The initial concentrations of products are 0.
Let us assume x is the change .
Please refer the attached picture.
Step 2 : Use the given value to find x
From the ICE table, we can see that at equilibrium, concentration of O₂ is x
But we have been given that , at equilibrium we have 0.190 mol of O₂ .
Let us convert this to concentration unit.
Concentration of O₂ at equilibrium =![\frac{mol}{L} = \frac{0.190mol}{4L} = 0.0475 M](/tpl/images/0079/3196/d0b26.png)
But concentration of O₂ from the ICE table is x.
Therefore we have x = 0.0475 M
Step 3 : Using x , find equilibrium concentrations
Using this value, let us write the equilibrium concentrations of the given species.
[SO₃]eq = 0.185 M - 2x = 0.185 - 2(0.0475) = 0.09 M
[SO₂]eq = 2x = 0.095 M
[O₂]eq = x = 0.0475 M
Step 4 : Set up equation for kc and solve it
The equilibrium constant kc is calculated as,
Let us plug in the above equilibrium values.
The equilibrium constant kc is 4.76 x 10⁻³
Ответ:
isolation
Explanation: