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rubyhart522
12.10.2019 •
Chemistry
At which temperature would a 40-gram kcl per 100 grams of water solution, be considered supersaturated?
30°
50°
70°
80°
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Ответ:
Ответ:
No
Explanation:
We first find the solubility of the copper sulphate salt
Number of moles= 4.6 moles
Volume =1.75 L
Molarity= number of moles/ volume = 4.6/1.75= 2.6 molL-1
Hence, only 2.6 moles of Copper II sulphate dissolves in 1.75L of water. Hence 4.6 moles of copper II Sulphate dies not dissolve in 1.75 L of water.