Calculate the empirical formula of a compound that has a composition of 5.9% (by mass) hydrogen and 94.1% (by mass) oxygen.

Oxygen O at 94.1% and H at 5.9%

Assume 100grams.

94% = 0.941 x 100gm. = 94.1 gm x 1mole/16gm. = 5.88 moles of O

5.9% = 0.059 x 100gm. = 5.9gm. X 1moleH/1.002gm. = 5.88 moles of H

$11.00

Because  .70 + .10 = .80

.80 times 55 = 44

55 - 44 = 11

If you add tax however, it would be 11.66.

Because 11 times .06 = .66

.66 + 11 = 11.66

Step-by-step explanation:

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