sarah121868
22.04.2020 •
Chemistry
Calculate the volume of H2(g) at 273 K and 2.00 atm that will be formed when 275 mL of 0.725 M HCl solution reacts with excess Mg to give hydrogen gas and aqueous magnesium chloride
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Ответ:
The volume of H2 is 1.117 L
Explanation:
Step 1: Data given
Temperature of H2 = 273 K
Pressure of H2 = 2.00 atm
Molarity of HCl = 0.725 M HCl
Volume of HCl = 275 mL = 0.275 L
Mg is in excess
Step 2: The balanced eqquation
Mg + 2HCl → MgCl2 + H2
Step 3: Calculate moles HCl
Moles HCl = molarity * volume
Moles HCl = 0.725 M * 0.275 L
Moles HCl = 0.199375 moles
Step 4: Calculate moles H2
For 1 mol Mg we need 2 mole HCl to produce 1 mol MgCl2 and 1 mol H2
For 0.199375 moles HCl we'll have 0.199375/2 = 0.0996875 moles H2
Step 5: Calculate volume H2
p*V = n*R*T
⇒with p = the pressure of H2 = 2.0 atm
⇒with V = the volume of H2 = TO BE DETERMINED
⇒with n = the moles of H2 = 0.0996875 moles
⇒with R = the gas constant = 0.08206 L*atm/mol*K
⇒with T = the temperature = 273 K
V = (n*R*T) / p
V = (0.0996875 * 0.08206 * 273) / 2.0
V = 1.117 L
The volume of H2 is 1.117 L
Ответ: