chromium (iii) or chromium(ii) are frequently used to apply chrome finish to sink fixtures such as faucets. if 45.2 Amps flow through a solution of chromium (iii) for 2 hours, how many grams of chromium can be deposited on a fixture A...175.35g B...58.45g c...0.016g d0.974g

58.45g

Explanation:

molar mass of chromium = 52g/mol

Q = it

i = 45.2amp

t = 2x60x60 = 7200sec

c = 3+

F = 96500

mass/molar mass = Q/CF

mass/52=(45.2x7200)/3x96500

mass/52 = (325440)/289500

mass/52 = 1.124

mass =52 x 1.124 = 58.45g

mass = 58.45g

Alright, lets get started.

Two sides of the rectange are 14 and s.

So, the area of the rectange would be =

So, the area of the rectange would be =

A triangle is cut from the rectangle.

The height of the triangle is =

The base of the triangle is = 14

So area of the triangle would be =

area of the triangle would be =

area of the triangle would be =

So, the area of shaded region = area of rectange - area of triangle

the area of shaded region =

As per given in question, area of shaded region is 84, hence

equation

So, this is the equation for s : Answer

Hope it will help :)