Determine the mass of water in kg, if 4300 cal of energy is placed in water, resulting in a temperature change to 101.0 oC from 92.5 oC.

0.5059kg

Explanation:

The heat absorbed for the water is determined using the equation:7

Q = C×m×ΔT

Where Q is heat absorbed (4300cal)

C is specific heat (1cal/g°C)

m is the mass in grams

ΔT is change in °C (101.0°C - 92.5°C = 8.5°C)

Replacing:

4300cal = 1cal/g°C×m×8.5°C

505.9g = m

In kg, the mass of water is:

108

Step-by-step explanation: −4×(−2−1)×(−2−1)×(−2−1)

−4×−3×−3×−3

12×−3×−3

−36×−3

108